Question

Find the direction ratio of the line x-1/2=3y=2z+3/4

Answer 1

x-1/2 = 3y = 2z+3 / 4

(x-1) / 2 = (y - 0) / (1/3) = (z + 3/2) / 2

On comparing with the standard form,

a = 2

b = 1/3

c = 2

Thus, dr's = ( 2, 1/3, 2 ).....●

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Hope it was helpful.

Answer 2

The direction ratio of the line $x-\dfrac{1}{2} =3y=\dfrac{2z+3}{4}$ are 2, $\dfrac{1}{3}$ and 2.

Step-by-step explanation:

Given by the question:

$x-\dfrac{1}{2} =3y=\dfrac{2z+3}{4}$

T find the direction ratio of the $x-\dfrac{1}{2} =3y=\dfrac{2z+3}{4}=?$

∴ $x-\dfrac{1}{2} =3y=\dfrac{2z+3}{4}$

⇒$x-\dfrac{1}{2} =\dfrac{y}{\dfrac{1}{3}} =\dfrac{\frac{2z+3}{2}}{\dfrac{4}{2} }$

⇒$\dfrac{x-\dfrac{1}{2}}{1}  =\dfrac{y}{\dfrac{1}{3}} =\dfrac{z+\frac{3}{2}}{2}$

Direction ratio = 2, $\dfrac{1}{3}$ and 2

∴  The direction ratio of the line $x-\dfrac{1}{2} =3y=\dfrac{2z+3}{4}$ are 2, $\dfrac{1}{3}$ and 2.

Hence, the direction ratio of the line $x-\dfrac{1}{2} =3y=\dfrac{2z+3}{4}$ are 2, $\dfrac{1}{3}$ and 2.