Find the discriminant for the following quadratic equations. Also, determine the nature of the roots.
(i) 5x²–6x–2=0
(ii) x²-3√3x+12=0
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Step-by-step explanation:
(i)D=b²-4ac
=(-6)²-4(5)(-2)
=36-4(-10)
=36+40
=76
Here b²-4ac > 0 hence real roots
(ii)D=b²-4ac
=(-3√3)²-4(1)(12)
=27-4(12)
=27-48
=(-21)
Here b²-4ac < 0 hence non real roots
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