Math, asked by yaminomar69, 9 months ago

find the discriminant of quadratic equation
 3\sqrt{3}x {}^{2}  + 10x +  \sqrt{3 }  + 3=0

Answers

Answered by dineshsahu8024
42

find the discriminant of quadratic equation

 3\sqrt{3}x {}^{2} + 10x + \sqrt{3 } + 3=0

Answered by pukultanvi4444
3

Answer:

x=−0.8387906438424395,−1.085710253456313

Step-by-step explanation:

Let's solve your equation step-by-step.

3√3x²+10x+√3+3=0

5.196152x²+10x+4.732051=0

For this equation: a=5.196152422706632, b=10, c=4.732050807568877

5.196152x²+10x+4.732051=0

Step 1: Use quadratic formula with a=5.196152422706632, b=10, c=4.732050807568877.

x=−b±√b2−4ac/2a

x=−(10)±√(10)²−4(5.196152)(4.732051)/2(5.196152)

x=−10±√1.646171

10.392304845413264

x=−0.8387906438424395,−1.085710253456313

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