Question

Find the discriminant of quadratic equation x2-4x+1=0

Answer 1

Step-by-step explanation:

Hi,

X² - 4x + 1

Here,

Coefficient of x² = a = 1

Coefficient of x = b = -4

And,

Constant term = c = 1.

Therefore,

Discriminant ( D ) b² - 4ac

=> (-4)² - 4 × 1 × 1

=> 16 - 4

=> 12.

Hence,

Discriminant = 12.

Hope it will help you:)

Answer 2

Given:

A quadratic equation x² - 4x + 1 = 0.

To Find:

The value of the determinant of the given quadratic equation.

Solution:

The given problem can be solved using the concepts of quadratic equations.    

1. The given quadratic equation is x² - 4x + 1 = 0.

2. For an equation to have equal roots the value of the discriminant is 0,  

=> The discriminant of a quadratic equation ax² + b x + c = 0 is given by the formula,  

=> Discriminant ( D ) = $\sqrt{b^2-4ac}$.  

3. Substitute the values in the above formula,  

=> √[(4)² - 4(1)(1)] = D,

=> D = √[(4)² - 4(1)(1)]

=> D = √(12).

=> D = 2√3.

Therefore, the value of the determinant is √(12) (OR) 2√3.