find the discriminant of quartic equation 3√2 x square-√3x-√18=0
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here, eq is 3√2x²-√3x-√18=0
a=3√2, b=-√3, c=-√18
D=b²-4ac
= (-√3)² -4(3√2)(-√18)
= 3 - 4(-3√36)
= 3-4(-3×6)
= 3-4(-18)
= 3+72
=75
a=3√2, b=-√3, c=-√18
D=b²-4ac
= (-√3)² -4(3√2)(-√18)
= 3 - 4(-3√36)
= 3-4(-3×6)
= 3-4(-18)
= 3+72
=75
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