Question

Find the discriminant of the equation 3x^2-2x+1/3=0

Answer 1

the equation is 3x² - 2x + 1/3 equal to b² - 4ac where

b = (-2)

a = 3

c = 1/3

putting the above values in the equation of d

= (-2)² - 4(3)(1/3)

( 3 gets cancelled because in multiplication )

= 4 - 4

= 0, ans.

Answer 2

Answer:

D=0

Step-by-step explanation:

$3 {x}^{2} - 2x + \frac{1}{3} = 0 \\ ta king \: lcm \: of \: 3 \: \\ 9 {x}^{2} - 6x + 1 = 0 \\ a = 9 \\ b = - 6 \\ c = 1$

D =

${b}^{2} - 4ac \\ = ( { - 6})^{2} - 4(9)(1) \\ = 36 - 36 \\ = 0$

Therfore nature of the roots is real.

Hope it helps you