Find the quadratic polynomial whose zeros and minus 4 and 3 and verify the relationship between the zeros and the coefficient
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Answer:
X²+X-12=0
Step-by-step explanation:
A quadratic polynomial with roots(zeroes) α and β can be written as
(X-α)(X-β)=0
Here, α=-4 and β=3,
So the equation becomes
(X-(-4))(X-3)=0
(X+4)(X-3)=0
Open the terms by multiplying
X²+X-12=0
This is your answer.
Relationship between zeroes and coefficients:
General quadratic equation
aX²+bX+C=0
We have X²+X-12=0
On comparing,we get a=1,b=1,c=-12
As we know,
Sum of roots =α+β=-4+3=-1 (which is also equal to -b/a=-1/1=-1)
Product of roots=α×β=-4×3=-12(which is also equal to c/a=-12/-1=-12)
Hence,verified
Thank you
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