Question

find the discriminant of the following equation2x^+x-4=0

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Answer 1

Question:-

• Find the discriminant of the following quadratic equation.

Solution:-

Given equation,

$\sf 2{x}^{2} + x - 4 = 0$

Here,

coefficient of x² (a)=2

coefficient of x (b)= -1

coefficient of $\sf x^{0}$ (c)= -4

So,

discriminant

$\sf = {b}^{2} - 4ac$

$\sf = 1 - 4 \times 2 \times -4$

$\sf =33$

Hence, discriminant=33.

Answer 2

Step-by-step explanation:

$2 {x}^{2} + x - 4 = 0 \\ a = 2 \: \: \: \: \: b = 1 \: \: \: \: c = - 4$

$2 {x}^{2} + x - 4 = 0 \\ discriminant = {b }^{2} - 4ac \\ = {1}^{2} - 4 \times 2 \times - 4 \\ = 1 + 32 \\ = 33 \\therefore \: \: \: \: {b}^{2} - 4ac > 0$