Question

find the discriminant of the point 3√2xsquare-√3x-√18=0

Answer 1

hii.....here is your ans..

we know that D(discriminant) = b^2-4ac
here....a=3√2 ,b=√3 ,C=√18
so by putting the value.....
D=b^2-4ac
D=(-√3)^2-4×3√2×(-√18)
D=3+12√2×√18
D=3+12√2×3√2
D=3+36×2
D=3+72=75 ans....

hope it helps you........

Answer 2

Hi,

Here's ur answer :-

There is a formula for discriminant.

D = b^2 - 4ac

A quadratic equation has form :-
ax^2+bx+c, where a,b,c are constant terms and x is a variable.

In the equation,
3root2 x^2 -root3 x -root18 = 0

a &b&c here are 3root2, -root3,& -root 18 respectively.

b^2-4ac = (-root3) ^2 -4 x 3root2 x -root 18 = 3 + 72 = 75

Thus, the discriminant is 75.

HOPE IT HELPS (^_^)

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