Question

Find the discriminant of the quadratic equation 2x2+x+4=0,hence find the nature of it's roots

Answer 1

Answer:

your answer is

Step-by-step explanation:

2*2+x+4=0

4+(4-4)x+4=0

4+4x-4x+4=0

4(1+x)-4(x+1)=0

(x+1)(4-1)=0

x+1=0 or, 4-1=3

x=-1

hope it help uu

Answer 2

The discriminant of equation $2x^{2}$ + x + 4 = 0 is -31, which means that the roots of the equation are complex and non-real, and the equation has no real solution.

The discriminant of a quadratic equation $ax^{2}$ + bx + c = 0 is given by the formula $b^{2}$ - 4ac. The discriminant determines the nature of the roots of the equation.

For the quadratic equation $2x^{2}$+ x + 4 = 0, we have a = 2, b = 1, and c = 4. Substituting these values into the formula, we find that the discriminant is:

$b^{2}$ - 4ac = $1^{2}$ - 4 * 2 * 4 = 1 - 32 = -31

Since the discriminant is negative, this indicates that the roots of the equation are complex and non-real. The equation has no real solution.

For more such questions on the quadratic equation: https://brainly.in/question/26754921

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