Question

Find the discriminant of the quadratic equation 3 root 3 x squared +10x+root 3 =0

Answer 1

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Answer 2

Answer:

$x=−0.192450089738,−1.73205080764$

Step-by-step explanation:

Given : $3 \sqrt{3}x^2+10x+ \sqrt{3}=0$

To Find: Find the discriminant of the quadratic equation

Solution:

Formula of discriminant = $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a = 3√3

b = 10

c = √3

Substitute the value in the formula :

$x=\frac{-10\pm\sqrt{10^2-4(3\sqrt{3}) \times{\sqrt{3}}}{2\times 3\sqrt{3}}$

$x=\frac{-10+\sqrt{100-36}}{10.392304845},\frac{-10-\sqrt{100-36}}{10.392304845}$

$x=\frac{-10+\sqrt{64}}{10.392304845},\frac{-10-\sqrt{64}}{10.392304845}$

$x=\frac{-10+8}{10.392304845},\frac{-10-8}{10.392304845}$

$x=\frac{-2}{10.392304845},\frac{-18}{10.392304845}$

$x=−0.192450089738,−1.73205080764$