Question

find the discriminant of the quadratic equation 3y^2-3y+2=0 and hence find the nature of roots

Answer 1

a = 3
b = -3
c = 2

Discriminant = b^2 - 4ac
= (-3)^2 - 4(3)(2)
= 9 - 24
= -15

Since, D < 0 therefore there is no real roots exist or we can say this equation has imaginary roots.

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Answer 2

Heya !!!


3Y² - 3Y + 2 = 0


Here,

A = 3 , B = -3 and C = 2


Discriminant (D) = B²-4AC


=> (-3)² - 4 × 3 × 2


=> 9 -24

=> -15


Hence,


Discriminant of this equation is -15.


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