Question

Find the discriminant
x²-3x-10 {D=b²-4ac}​

Answer 1

Answer:

The root of equations is

X= +5, -2

Answer 2

Answer:

$x^2-3x-10=0$

$D=b^2-4ac$

$a=1, b=-3, c=-10$

$D=(-3)^2-4(1)(-10)$

$D= 9+40 = 49$