Question

find the discriminate in each of the following quadratic equations. (1) √3x^2 - 2√2x - 2 √3=0

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Answer 1

Step-by-step explanation:

b^2-4ac

(-2√2)^2-4(√3)(-2√3)

(8)-4(√3)(-2√3)

8-4(-6)

8+24

32

Answer 2

Solution:

To find discriminant, we have formula:

⇒D =b²-4ac

Here,

• D=Discriminant

• b=coefficient of x

• a=coefficient of x²

• c=Constant term

By substituting all values:

D=(-2√2)²-4(√3)(-2√3)

D=8+24

D=32

Required value of D is 32.

More:-

• When value of D is +ve then the quadratic equation will have two distinct roots.

• When value of D is -ve then the quadratic equation will have no real roots.

• When value of D is 0 then the quadratic equation will have two equal roots.