Find the displacement of a particle if its position vector changes from r1=2i+3j+5k
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¶ Complete question would be -
Find the displacement of the particle of its position vector changes from r1=2i+3j+5k to r2=4i+5j+2k. Also find the the distance travelled by the particle along X,Y,Z axes respectively. All distance are in metre.
# Given -
r1 = 2i + 3j + 5k
r2 = 4i + 5j + 2k
# Solution -
Displacement of the particle is calculated as -
s = r2 - r1
s = (4i + 5j + 2k) - (2i + 3j + 5k)
s = (4-2)i + (5-3)j + (2-5)k
s = 2i + 2j - 3k
$ Distance of the particle from different axes -
- From X-axis, 2 m.
- From Y-axis, 2 m.
- From Z-axis, 3 m.
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