Question

Find the displacement of an air particle 3.5 m from the origin of disturbance at t=0.05 s,
when a wave of amplitude 0.2 mm and frequency 500 Hz travels along it with a velocity
350 m/s.
​

Answer 1

Answer:

Displacement of the air particle at given position and given time is ZERO

Explanation:

As we know that the equation of wave is given as

$y = A sin(\omega t - kx)$

here we know that

$\omega = 2\pi f$

$\omega = 2\pi(500) = 1000 \pi$

$\frac{\omega}{k} = v$

here we know that

$v = 350 m/s$

$\frac{1000\pi}{k} = 350$

$k = 8.97$

now we have

$y = A sin(1000\pi t - 8.97 x)$

so we have

$y = (0.2mm)sin(1000\pi (0.05) - 8.97 (3.5))$

$y = 0$

#Learn

Topic : Travelling wave

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