Question

Find the displacement vector of a particle starting at (3,4,8) and moving towards (-2,4,1). 2. Find the angle displacement vector makes with x-axis in previous question?

Answer 1

Answer:

Solve for the displacement in two or three dimensions. ... We generally use the coordinates x, y, and z to locate a particle at point P(x, y, z) in three dimensions. ... Δ→r=→ r(t2 .

Answer 2

Answer:

given that

p1=(3,4,5) and p2=(-2,4,1)

displacement vector is given by

r=(x2-x1)i +(y2-y1)j +(z2-z1)k

r=(-2-3)i+(4-4)j +(1-5)k

r=-5i +0j -4k

r=-5i -4k

so we have rx=-5 and ry=0

therefore angle with x axis

tan(Ф)=ry/rx=0/-5=0

Ф=arctan(0)=0

Ф=0 degree

Explanation: