Question

Find the distance and displacement from the graph between the time interval 0s and 10s

Answer 1

We know that,

• Distance travelled, is the total area between the velocity - time graph.

So,

Area of $\Delta$ABC,

• ½ × base × height
• ½ × 5 × 20
• 10 × 5
• 50

Area of $\Delta$CDE

• ½ × base × height
• ½ × 5 × 10
• 5 × 5
• 25

So, the total distance travelled will be 25 + 50 = 75m.

Now, for the displacement,

• We have subtract the positive area of graph from the negative.
• So, 50 - 25 = 25 m

Thus, the total distance covered will be 75m and the total displacement is 25m.