Question

Find the distance b/w the points
(cosθ + sinθ , 0) & (0 , sinθ - cosθ) ​

Answer 1

Answer:

So distance between two points D = √{ (sinθ - cos θ)² +(cos θ+ sinθ)²}

D = √[ (sinθ )² + (cos θ)² - 2 sin θ cosθ +(cos θ )² + ( sin θ) ² +2 cos θ sinθ) ]

Since (sinθ )² + (cos θ)² = 1

Therefore

D= √[ ( 1 - 2 sin θ cosθ + 1 +2 cos θ sinθ) ]

Cancelling 2 sin θ cos θ and -2 cos θ sinθ)

D = √2

Step-by-step explanation:

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