Find the distance beetwen the line of 5x-12y-41=0 and thee point (3,0)
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Step-by-step explanation:
in a rectangle of perimeter one metre,one side is five centimetres
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Step-by-step explanation:
5x-12y-41 = 0
Place the normal numbers to the right side
5x-12y = 0+41
we can't add numbers with different variables So,
Ans= 5x-12y=41
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