Question

find the distance betwee point A(9,3)andB(15,11).​

Answer 1

Answer:

(9,3)

B (15,11)

\begin{gathered}AB = \sqrt{ (x_2-x_1)^{2} + (y_2-y_1)^{2}} \\\\ AB= \sqrt{ (15-9)^{2} + ( 11-3)^{2}}\\\\ AB = \sqrt{ (6)^{2} +(8)^{2} } \\\\ AB = \sqrt{ 36 +64}\\\\ AB =\sqrt{ 100} \\\\ AB = 10 unit\end{gathered}

AB=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

AB=

(15−9)

2

+(11−3)

2

AB=

(6)

2

+(8)

2

AB=

36+64

AB=

100

AB=10unit

Answer 2

Hey buddy here is your answer

Distance between A and B = √[(X2-X1)^2+(Y2-Y1)^2]

                                                √[(15-9)^2+(11-3)^2]

                                                √[(6)^2+(8)^2]

                                                √[36+64]

                                                √100

                                                 10cm

Hope it helps

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