find the distance betwee point A(9,3)andB(15,11).
Answers
Answer:
(9,3)
B (15,11)
\begin{gathered}AB = \sqrt{ (x_2-x_1)^{2} + (y_2-y_1)^{2}} \\\\ AB= \sqrt{ (15-9)^{2} + ( 11-3)^{2}}\\\\ AB = \sqrt{ (6)^{2} +(8)^{2} } \\\\ AB = \sqrt{ 36 +64}\\\\ AB =\sqrt{ 100} \\\\ AB = 10 unit\end{gathered}
AB=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
AB=
(15−9)
2
+(11−3)
2
AB=
(6)
2
+(8)
2
AB=
36+64
AB=
100
AB=10unit
Hey buddy here is your answer
Distance between A and B = √[(X2-X1)^2+(Y2-Y1)^2]
√[(15-9)^2+(11-3)^2]
√[(6)^2+(8)^2]
√[36+64]
√100
10cm
Hope it helps
Mark the brainliest and click the thanks button plz plz
And don't forget to follow me