find the distance between (1,7)and (4,2)
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let, co- ordinate of point (1,7) along x and y axis is x1 = 1 and y1 = 7
similarly , for point (4,2) x2 = 4 and y2 = 2
consider (^ ) = square
using ,distance formula = √[( x2 - x1)^ + (y2 - y1)^
putting values of x1, x2 ,y1,y2 in d.formula
distance b/w points = √[(4 - 1)^ +(2-7)^]
=√[(3)^ +(-5)^]
= √(9 + 25)
= √34 units
similarly , for point (4,2) x2 = 4 and y2 = 2
consider (^ ) = square
using ,distance formula = √[( x2 - x1)^ + (y2 - y1)^
putting values of x1, x2 ,y1,y2 in d.formula
distance b/w points = √[(4 - 1)^ +(2-7)^]
=√[(3)^ +(-5)^]
= √(9 + 25)
= √34 units
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