find the distance between (2,1,0) and 2x+y+2z+5=0
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Hello student
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Given planes are2x + y + 2z = 8 and 4x + 2y + 4z + 5 = 0
multiplying 1stequation by 2 we get
4x+2y+4z=16 and 4x+2y+4z=-5
distance between the planes=16-(-5)/sqrt(42+22+42)
=21/6=7/2
HOPE , IT HELPS .
FOLLOW ME .✌
------------------------------------------
Given planes are2x + y + 2z = 8 and 4x + 2y + 4z + 5 = 0
multiplying 1stequation by 2 we get
4x+2y+4z=16 and 4x+2y+4z=-5
distance between the planes=16-(-5)/sqrt(42+22+42)
=21/6=7/2
HOPE , IT HELPS .
FOLLOW ME .✌
cristal:
what to do if a point and a plane is given
4 what
will u pls ans this question
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