Question

find the distance between A(2,3) and B(4,1)​

Answer 1

(x1, y1) = (2,3)

(x2, y2) =(4,1)

$d = \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} }$

$= \sqrt{(4 - 2) {}^{2} + (1 - 3) {}^{2} } \\ \\ = \sqrt{(2) {}^{2} + (- 2) {}^{2} } \\ \\ = \sqrt{4 + 4} \\ \\ = \sqrt{8} \\ \\ = 2 \sqrt{2}$

✌✌hope it's help you ✌✌

thank you ❤❤

Answer 2

A(2,3)--------------------B (4,1)

AB^2=(4-2)^2+(1-3)^2
=4+(-2)^2
=4+4
AB^2 =8
=2underoot2
$2 \sqrt{ 2}$