find the distance between A(4-6) B(3-2)
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Answered by
0
Eccentric angle of one of the points on the ellips x
2
+3y
2
=6 at a distance 2 units from the centre of the ellips is
4
kπ
, then k is
Answered by
0
d(A,B) = √(x2-x1)² + (y2-y1)²
= √(3-4)²+[(-2)-(-6)]²
= √(3-4)²+[-2+6]²
=√(-1)²+(4)²
=√1+16
=√17
The distance between A(4-6) B(3-2) is √17 units.
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