Question

find the distance between P(1,-3) and Q(4,-6)

Answer 1

Answer:

Given

P=(1,-3)

Q=(4,-6)

$distance \: = \sqrt{(x2 - x1) { \:}^{2} + (y2 - y1) {}^{2} }$

$= \sqrt{4 - 1) { }^{2} + (- 6 + 3) {}^{2} }$

$= 3 \sqrt{2}$ units

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Answer 2

let

P(1,-3)=(X1,y1)

Q(4,-6)=(X2,y2)

distance between two points is √(x2-x1)^2+(y2-y1)^2

substitute above values in the formula

√(4-1)^2+(-6-(-3)

√(3)^2+(-3)^2

√9+9

√18

3√2 units