Question

Find the distance between

P( - 4 , 7 ) and Q ( 2 , - 5 )

Answer 1

Hey mate !
Here is your answer.
P(-4, 7) and Q(2, -5)
By using distance formula
PQ=√[(x2-x1)^2 +(y2 - y1)^2]
=√[(2-(-4))^2+(-5-(-4))^2]
=√[(6)^2+(-1)^2]
=√36+1
=√37 units.
Hope it helps you .

Answer 2

HOLA

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$pq= \sqrt{(2 - ( - 4) {}^{2}) + (( - 5) \: - 7) {}^{2} } \\ \\ pq \: = \: \sqrt{(6) {}^{2} + \: ( - 12) {}^{2} } \\ \\ pq \: = \: \sqrt{36 \: + \: ( - 144)} = \sqrt{180} \\ \\ pq \: = \: \sqrt{180} = \: \sqrt{36 \: \times \: 5} = 6 \sqrt{5}$

So the distance is 6√5

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HOPE U UNDERSTAND ❤❤❤