find the distance between p (a sin theta, a cos theta ) and (a cos theta, minus a sin theta )
Answers
Answered by
2
Step-by-step explanation:
Distance
PQ = √(aCosO - aSinO)² + (-aSinO - aCosO)²
= √(aCosO - aSinO)² + (aCosO + aSinO)²
= √2(a²Cos²O + a²Sin²O)
= √2a²
= √2*a = a√2 unit
Answered by
0
Answer:
PQ=√( acos0 - asin0)²+(-asin0-acos0)²
PQ=√(acos0-asion0)²+(asion0+acos0)²
PQ=√(2(a²cos²0+a²sin²0)
PQ=√2(a²(cos²0+sin²0)
{cos²0+cos²0= 1}
PQ=√2(a²)
PQ=√2a
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