Question

. Find the distance between points ( 1 , 2 ) and ( 4 , 6 )

Answer 1

Step-by-step explanation:

Let A( 1, 2) and B(4, 6)

Using distance formula of coordinate Geometry,

AP =

$\sqrt{(4 - 1) ^{2} + (6 - 2)^{2} } \\ = \sqrt{3^{2} + 4^{2} } \\ = \sqrt{25} \\ = 5$

hence, the distance between (1,2) and (4,6) will be 5 units.

Answer 2

Given :  points ( 1 , 2 ) and ( 4 , 6 )

To Find :  the distance between points ( 1 , 2 ) and ( 4 , 6 )

Solution:

Distance between point (x₁ , y₁ )  and (x₂ , y₂)  is given by

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

points ( 1 , 2 ) and ( 4 , 6 )

x₁ = 1

x₂ = 4

y₁ = 2

y₂ = 6

the distance between points ( 1 , 2 ) and ( 4 , 6 )

 $\sqrt{(4-1)^2+(6-2)^2}$

$=\sqrt{(3)^2+(4)^2}$

$=\sqrt{9+16}$

$=\sqrt{25}$

= ±5

as Distance can not be negative

Hence the distance between points ( 1 , 2 ) and ( 4 , 6 )  is 5

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