Question

find the distance between the following Paris of points are (3, 4) and (-7, 2)​

Answer 1

Given point are

$\sf \to(3,4) \: and \: ( - 7,2)$

To Find the distance between point

Forward

$\to\sf \: D = \sqrt{(x_{2} - x_1)^{2} + (y_2 - y_1)^{2} }$

We Have

$\sf \to(x_1 = 3,y_1 = 4) \: and \: ( x_2 = - 7,y_2 = 2)$

Now Put the Value

$\to \sf \: D = \sqrt{( - 7 - 3)^{2} + (2 - 4)^{2} }$

$\to \sf \: D = \sqrt{( - 10)^{2} + ( - 2)^{2} }$

$\to \sf \: D = \sqrt{100 + 4}$

$\to \sf \: D = \sqrt{104} \: sq \: unit$

So the distance between point are √(104)sq unit

Some formula

Distance Formula

$\to\sf \: D = \sqrt{(x_{2} - x_1)^{2} + (y_2 - y_1)^{2} }$

Section Formula

$\sf \to \: \bigg( \dfrac{x _{2}m +x_1n }{m + n} , \dfrac{y_2m + y_1n}{m + n} \bigg)$

Mid Point

$\sf \to \: \bigg( \dfrac{x _{2} +x_1 }{2} , \dfrac{y_2 + y_1}{2} \bigg)$

Answer 2

Answer:

1 by distance formula

2 (3-(-7) + (4-2) is in square

(10)+(2) square

the square of 10 is 100

the square of 2 is 4

100+4=104 in root