Question

find the distance between the lines 3x+2y=5and 6x+2y=6​

Answer 1

$\huge\underline{\underline{\sf{ \color{lime}{Answer:-} }}}$

To find :-

x + y

lets solve it ....

6x + $\cancel{2}$ = 6 ....1

3x + $\cancel{2}$ = 5

-ㅤ-ㅤㅤㅤ-

____________

3x = 1

____________

so,

x = $\dfrac{1}{3}$

Now,

put value of x in eq 1

$\implies$ 6 × $\dfrac{1}{3}$ + 2y = 6

$\implies$ $\dfrac{6}{3}$ + 2y = 6

$\implies$ $\cancel{\dfrac{6}{3}}$ + 2y = 6

$\implies$ 2 + 2y = 6

$\implies$ 2y = 6 - 2

$\implies$ 2y = 4

$\implies$ y = $\dfrac{4}{2}$

$\implies$ y = $\cancel{\dfrac{4}{2}}$

$\implies$ y = 2

So,

x + y = $\dfrac{1}{3}$ + 2

x+ y = $\dfrac{1\:+\:6}{3}$

$\therefore$ x + y = $\dfrac{7}{3}$

_______________________________________________

SOLVED ♡

Answer 2

$\huge\underline{\underline{\sf{ \color{lime}{Answer:-} }}}$

To find :-

x + y

lets solve it ....

6x + $\cancel{2}$ = 6 ....1

3x + $\cancel{2}$ = 5

-ㅤ-ㅤㅤㅤ-

____________

3x = 1

____________

so,

x = $\dfrac{1}{3}$

Now,

put value of x in eq 1

$\implies$ 6 × $\dfrac{1}{3}$ + 2y = 6

$\implies$ $\dfrac{6}{3}$ + 2y = 6

$\implies$ $\cancel{\dfrac{6}{3}}$ + 2y = 6

$\implies$ 2 + 2y = 6

$\implies$ 2y = 6 - 2

$\implies$ 2y = 4

$\implies$ y = $\dfrac{4}{2}$

$\implies$ y = $\cancel{\dfrac{4}{2}}$

$\implies$ y = 2

So,

x + y = $\dfrac{1}{3}$ + 2

x+ y = $\dfrac{1\:+\:6}{3}$

$\therefore$ x + y = $\dfrac{7}{3}$

_______________________________________________

SOLVED ♡