Question

Find the distance between the lines 3x+6=0 and x-7=0.

Answer 1

Distance bewteen two lines
√(x1-x2)^2+(y1-y2)^2
=√(3-1)^2+(6+7)^2
=√4+169
=√173
=13.16

Answer 2

Answer:

The distance between the lines is 9 unit.

Step-by-step explanation:

Given : Lines 3x+6=0 and x-7=0.

To find : The distance between the lines ?

Solution :

Line $3x+6=0$

$3x=-6$

$x=-2$

Point (-2,0)

Line $x-7=0$

$x=7$

Point (7,0)

Now, the distance between points is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(7-(-2))^2+(0-0)^2}$

$d=\sqrt{(9)^2}$

$d=9$

The distance between the lines is 9 unit.