Question

Find the distance between the mid point
of the line segment AB and the point
(3,-1, 2) where A = (6,3,-4), B(-2,-1,2)


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Answer 1

Answer:

✓14

Step-by-step explanation:

mid point of AB

x=6-2/2=2

y=3-1/2=1

z= -4+2/2= -1

mid point = (2,1,-1) (x1,y1,z1)

point = (3,-1,2) (x2,y2,z2)

Distance = √(x2-x1)^2+(y2-y1)^2+(z2-z1)^2

= √ (3-2)^2+(-1-1)^2+(2+1)^2

= √1+4+9

= √14