Question

find the distance between the parallel lines x+3y-7=0 and 3x+9y+8=0​

Answer 1

Step-by-step explanation:

solving eq 1 & 2

x+3y-7=0 and 3x-9y+8=0

x+3y = 7

y = (7-x )/3

putting it in 2nd one

3x + 9 (7-x )/3 = -8

3x -21 +3× = -8

6x = 21-8

6x = 13

x = 13/6