Question

find the distance between the parallel sides of length 25 36 of the trapezium whose area is 366 m square​

Answer 1

area of trapezium =366m²

1/2 ×(sum of //sides) ×height = 366m²

1/2×(25+36) × h =366m²

1/2 ×(61) ×h =366 m²

61 ×h = 366 ×2

h =366×2/61

h =12m

Answer 2

Given:-

• Length of sides of trapezium is 25 metres and 36 metres.
• Area of trapezium is 366² metres.

To Find:-

• Distance between their sides?

Solution:-

Area of trapezium

$\dag{ \boxed{ \underline{ \rm { \blue{½ \times (a + b) \times h}}}}}$

Where,

a and b = sides

h = height

According to the question

$\rm→ 366 = ½ \times (25 + 36) \times h \\ \\ \rm→ 366 = ½ \times (61 ) \times h \\ \\ \rm→ 366 = 30.5 \times h \\ \\ \rm→ \frac{366}{30.5} = h \\ \\ \rm→ 12 = h$

Hence, the difference between their lengths is 12 cm.