Question

find the distance between the point P (a+b), (a-b) q (a-b),(a+b)

Answer 1

Refer to the attachment.


If you have any questions just comment.

Answer 2

Answer:

The distance between the point P and point Q is $2 \sqrt{2}\ b\ units$.

Step-by-step explanation:

Formula

$Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

As given

The distance between the point P (a+b), (a-b) Q(a-b),(a+b) .

Putting values in the formula

$PQ = \sqrt{(a-b-(a+b))^{2}+(a+b-(a-b))^{2}}$

$PQ = \sqrt{(a-b-a-b)^{2}+(a+b-a+b)^{2}}$

Simplify the above

$PQ = \sqrt{(-b-b)^{2}+(b+b)^{2}}$

$PQ = \sqrt{(-2b)^{2}+(2b)^{2}}$

$PQ = \sqrt{4b^{2}+4b^{2}}$

$PQ = \sqrt{8b^{2}}$

$\sqrt{8}=2\sqrt{2}$

Thus

$PQ = 2 \sqrt{2}\ b\ units$

Therefore the distance between the point P and point Q is $2 \sqrt{2}\ b\ units$.