find the distance between the points (1, 5) and (5, 8).
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Answered by
7
hloo
x1 = 1
x2 = 5
y1 = 5
y2 = 8
we know that
√(5-1)^2+(5-8)^2
=√(4)^2+(-3)^2
=√16+9=√25 = 5 units
x1 = 1
x2 = 5
y1 = 5
y2 = 8
we know that
√(5-1)^2+(5-8)^2
=√(4)^2+(-3)^2
=√16+9=√25 = 5 units
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Answered by
5
x1 =1 and x2 =5 and y1=5 and y2=8 so,
Distance between the two points =√(x2-x1)^2+(y2-y1)^2
=√(5-1)^2+(8-5)^2
=√(4)^2+(3)^2
=√16+9=√25 = 5 units
Distance between the two points =√(x2-x1)^2+(y2-y1)^2
=√(5-1)^2+(8-5)^2
=√(4)^2+(3)^2
=√16+9=√25 = 5 units
make me brainliest answer vote and thank me
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