*Find the distance between the points (5, −12) and (9, −9).*
1️⃣ 5
2️⃣ −5
3️⃣ √5
4️⃣ √205
Answers
Answer:
let the points be Pand Q
PQ=√(x²-x¹)²+(y²-y¹)²
= √( 9-5)²+(-9--12)²
= √16+9
= √25
PQ= 5
Given,
The co-ordinates of the given points are = (5,-12) and (9,-9)
To find,
The distance between the given two points.
Solution,
We can easily solve this mathematical problem by applying the distance measuring formula of the co-ordinate geometry.
Let,
(5,-12) = X1,Y1
(9,-9) = X2,Y2
(Assume, X1,X2,Y1,Y2 as variables to do the further mathematical calculations.)
So, the distance between the two points will be
= ✓(X2-X1)²+(Y2-Y1)²
= ✓(9-5)²+(-9+12)²
= ✓(4)²+(3)²
= ✓16+9
= ✓25
= 5 units
[Although, (-5)² is also 25, but the distance between two points cannot be negative, it can be only positive, so we will go for 5 units as the final answer. Negative value is only related to the displacement, where direction is a factor, but for distance the direction isn't the factor.]
Hence, ths distance between the two given points is 5 units (Option 1).