Question

find the distance between the points (-5,7) and (-1,3)​

Answer 1

Answer:

P≡(−5,7)

Q≡(−1,3)

∴d(P,Q)=

(−5−(−1))

2

+(7−3)

2

∴d(P,Q)=

16+16

∴d(P,Q)=

32

∴d(P,Q)=4

2

Take me to brainlist question

Answer 2

✬ The distance between the points is √32 units ✬

Step-by-step explanation:

Given points: (-5,7) and (-1,3)

To find: Distance between the points

Required Formula:

• Distance between the points = √(x₂ - x₁)² + (y₂ - y₁)²

❍ Let the points be A(x₁,y₁) is (-5,7) and B(x₂,y₂) is (-1,3).

Let's do it,

____________________________________

$\\ \dashrightarrow\sf{ AB= \sqrt{ { \bigg(</u></strong><strong><u>-</u></strong><strong><u>1 - ( - 5) \bigg)}^{2} + {\bigg(3 - 7 \bigg)}^{2} } } \\ \\ \dashrightarrow\sf{ AB= \sqrt{ { \bigg(</u></strong><strong><u>-</u></strong><strong><u>1 + 5 \bigg)}^{2} + { \bigg(3 - 7 \bigg)}^{2} } } \\ \\ \dashrightarrow\sf{ AB= \sqrt{{ \bigg(</u></strong><strong><u>4</u></strong><strong><u> \bigg)}^{2} + { \bigg( - 4 \bigg)}^{2}}}\\ \\ \dashrightarrow\sf{ AB= \sqrt{</u></strong><strong><u>1</u></strong><strong><u>6 + 16}} \\ \\ \dashrightarrow \underline{ \boxed{\frak{ AB = \sqrt{</u></strong><strong><u>3</u></strong><strong><u>2</u></strong><strong><u>} \: units}}} \: \red{ \bigstar}$

• Hence,The distance between the points is √32 units.