Question

Find the distance between the points (-7/5, 2) and (3/5, 3)​

Answer 1

$\mathtt{\huge{\fbox{SOLUTION}}}$

Given ,

The two points are (-7/5 , 2) and (3/5 , 3)

We know that , the distance between two points is given by

$\large \mathtt{\fbox{D = \sqrt{ {( x_{2} - x_{1} )}^{2} + {( y_{2} - y_{1} )}^{2} } } \: \: \: \: }$

Substitute the known values , we get

$\sf \hookrightarrow D = \sqrt{ {( \frac{3}{5} - ( - \frac{7}{5} ) )}^{2} + {(3 - 2)}^{2} } \\ \\\sf \hookrightarrow D = \sqrt{ {( \frac{3}{5} + \frac{7}{5} )}^{2} + {(3 - 2)}^{2} } \\ \\ \sf \hookrightarrow D = \sqrt{ {( \frac{3 + 7}{5} )}^{2} + {(3 - 2)}^{2} } \\ \\\sf \hookrightarrow D = \sqrt{ {( \frac{10}{5} )}^{2} + {(1)}^{2} } \\ \\\sf \hookrightarrow D = \sqrt{ \frac{100}{25} + 1 } \\ \\\sf \hookrightarrow D = \sqrt{ \frac{100 + 25}{25} } \\ \\ \sf \hookrightarrow D = \sqrt{\frac{125}{25} } \\ \\\sf \hookrightarrow D = \sqrt{5} \: \: units$

Hence , √5 units is the distance between two given points

Answer 2

Answer:

under root ( 3/5+7/5 +3-2)= under root 2