Question

Find the distance between the points (7,8) and (-2,3)​

Answer 1

Answer:

The distance between  these points is $\sqrt{106}$ unit .

Step-by-step explanation:

Given as :

The points are $x_1$  , $y_1$  = 7 , 8

And $x_2$ , $y_2$ = - 2 , 3

Let The distance between these points = D unit

∵ Distance = $\sqrt{(x_1 - x_2)^{2} + (y_1-y_2)^{2} }$

Or, D = $\sqrt{(7 + 2)^{2} + (8 - 3)^{2} }$

Or, D = $\sqrt{9^{2}+5^{2} }$

Or, D = $\sqrt{106}$ unit

Or The distance between  these points = D = $\sqrt{106}$ unit

Hence, The distance between  these points is $\sqrt{106}$ unit . Answer

Answer 2

Step-by-step explanation:

Given Find the distance between the points (7,8) and (-2,3)

• Let the coordinates of two points P and Q be (x1,y2) and (x2,y2) respectively.
• Therefore distance between two points is
• PQ = √ (y2 – y1)^2 + (x2 – x1)^2
• Now we get d = √(8 – 3)^2 + (7 + 2)^2 units
•         So d = √5^2 + 9^2 units
•       So d = √25 + 81 units

Therefore d = √106 units

Reference link will be

https://brainly.in/question/8033510