find the distance between the points (8, 6) and(3, 1)
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The distance between the points (8, 6) and (3, 1) is 5 sqrt(2) units.
- We employ the distance formula, which is provided by: to determine the separation between two places.
- sqrt((x2-x1) + (y2-y1)) = d
- where the coordinates for the two locations are (x1, y1) and (x2, y2).
- Using the supplied positions (8, 6) and (3, 1) as the inputs for this formula, we obtain:
d = sqrt((3-8)^2 + (1-6)^2)
= sqrt((-5)^2 + (-5)^2)
sqrt(50) = 5 squares(2)
- These points can be represented graphically to help us better grasp this. The coordinates (8, 6) and (3, 1) may be plotted on a coordinate plane, and a straight line can be drawn to link them. This line's length indicates how far apart the two points are from one another.
- The hypotenuse of a right triangle with five-legged legs is the distance between these two locations, according to the Pythagorean Theorem. The triangle is an isosceles right triangle since the lengths of the legs are equal, and the hypotenuse measures 5 square feet.(2).
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