find the distance between the points A and B if A(a+b,b-a),B(a-b,a+b
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Distace between the points (x, y) and (a+b, b-a) & (a-b, a+b) is equal ⇒ √{[x - (a + b)]2 + [y - (b -a)]2} = √{x - (a - b)]2 + [y - (a + b)]2} ⇒ x2 + (a + b)2 - 2x(a + b) + y2 + (b - a)2 - 2y(b - a) = x2 + (a - b)2 - 2x(a - b) + y2 + (a + b)2 - 2y(a + b) ⇒ -2ax - 2bx - 2by + 2ay = - 2ax + 2bx - 2ay - 2by ⇒ ay - bx = bx - ay ⇒ 2ay = 2bx ⇒ bx = ay Hence proved.
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Answered by
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Distance formula
√(x₂-x₁) + (y₂-y₁)
√(a-b-a-b)² + (a+b-b+a)²
√(-2b)²+ (2a)²
√4b²+ 4a²
√4(a²+b²)
2√(a²+b²)
√(x₂-x₁) + (y₂-y₁)
√(a-b-a-b)² + (a+b-b+a)²
√(-2b)²+ (2a)²
√4b²+ 4a²
√4(a²+b²)
2√(a²+b²)
amisha5069:
hey thank you for the easy method
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