Question

Find the distance between the points p(-1,1)and Q(5,-7).​

Answer 1

Given:-

P =(-1,1)

Q=(5,-7)

PQ= ✓(5+1)^2+(-7-1)^2

PQ=✓(6)^2+(8)^2

PQ=✓100 units

therefore,PQ=10units

Answer 2

Answer:

We know that, distance between two points is √(x2-x1)²+(y2-y1)²

PQ=√(5+1)²+(-7-1)²

=√36+64

=√100=10