Find the distance between the points P(-4,7) and Q(2,-5).
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Answered by
86
Heya !!!
The given points are A ( -4 , 7) and B ( 2 , -5)
Here,
X1 = -4 , Y2 = 7 and X2 = 2 , Y2= -5
Therefore,
AB = ✓( X2 - X1)² + (Y2-Y1)²
AB = ✓{(2 - (-4)}² + (-5-7)²
AB = ✓(6)² + (-12)²
AB = ✓36+144
AB = ✓180 = ✓36 × 5
AB = 6✓5 units.
★ HOPE IT WILL HELP YOU ★
The given points are A ( -4 , 7) and B ( 2 , -5)
Here,
X1 = -4 , Y2 = 7 and X2 = 2 , Y2= -5
Therefore,
AB = ✓( X2 - X1)² + (Y2-Y1)²
AB = ✓{(2 - (-4)}² + (-5-7)²
AB = ✓(6)² + (-12)²
AB = ✓36+144
AB = ✓180 = ✓36 × 5
AB = 6✓5 units.
★ HOPE IT WILL HELP YOU ★
shivanya1230:
thanks again
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12
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