Question

find the distance between the points p(-5,_4) and q (3,-7)

Answer 1

here is your answer.....

Answer 2

The distance between the points is 8.54 units

Step-by-step explanation:

p = (x_1,y_1)=(-5,-4)

q=(x_2,y_2)=(3,-7)

Formula : d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the values in the formula :

$d = \sqrt{(3-(-5))^2+(-7-(-4))^2}$

$d = \sqrt{(3+5)^2+(-7+4)^2}$

$d=\sqrt{73}$

d=8.54

Hence the distance between the points is 8.54 units

#Learn more:

Find the distance of point (-2,3) from  origin

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