Question

Find the distance between the points P(-6,7) and Q(-1,-5)

Answer 1

distance between PQ
= √[(x2 - x1)^2 + (y2 - y1 )^2 ]
= √[-1-(-6)] ^2+ [-5-7]^2
= √[-1+6]^2+ [-12]^2
= √[(5)^2 + 144]
= √(25+144)
= √169
= 13 units..

Answer 2

Heya,

pq = √ (x2-X1)^2 + (y2-y1)^2

√ (-1+6)^2+(-5-7)^2

√(5)^2+(-12)^2

√25 +144

√169

= 13 units Answer..

HOPE IT HELPS ^_^