Question

Find the distance between the points P(-7,-4) &Q(-2,8)

Answer 1

distance between PQ=√(x2-x1)²+(y2-y1)²

therefore.,think

P(-7,-4) andQ(-2 ,8)

x1 y1. x2 y2

=√(-2-(-7))²+(8-(-4))²

=√(-2+7)²+(8+4)²

=√(5)²+(12)²

=√25+144

=√169

=13cm

there fore

the distance between PQ=13cm

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