Math, asked by onoja4882, 1 year ago

xsquare-x-a(a+1)=0 find roots

Answers

Answered by Zaransha
0

 {x}^{2}  - x - a(a + 1) \\  \\  {x}^{2}  - ax  + (a + 1)x - a(a + 1) = 0 \\  \\ x(x - a) + (a + 1)(x - a)  = 0\\   \\ (x - a)(a + x + 1) = 0

So the roots will be,

x = a \\  \\  \\ and \\  \\ x =  - (a + 1)
Answered by nani3214
0

given

x²-x-a(a+1)

=x²-x-a²-a=0

Similar questions