Question

xsquare-x-a(a+1)=0 find roots

Answer 1

${x}^{2} - x - a(a + 1) \\ \\ {x}^{2} - ax + (a + 1)x - a(a + 1) = 0 \\ \\ x(x - a) + (a + 1)(x - a) = 0\\ \\ (x - a)(a + x + 1) = 0$

So the roots will be,

$x = a \\ \\ \\ and \\ \\ x = - (a + 1)$

Answer 2

given

x²-x-a(a+1)

=x²-x-a²-a=0