find the distance between the points (sin thetha/2,0) and (0, cos thetha/2)
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distance between joining of (x1,y1) and (x2,y2) is
√(x2-x1)²+(y2-y1)²
given (x1,y1) =(sin theta/2,0) and (x2,y2) = (0,cos theta/2)
distance = √[0-sintheta/2]² + [cos theta/2- 0]²
= √(sin ²theta/4 + cos² theta/4
=√(sin² theta + cos² theta) 4
= √1/4 {since sin² theta + cos²theta = 1}
=1/2
√(x2-x1)²+(y2-y1)²
given (x1,y1) =(sin theta/2,0) and (x2,y2) = (0,cos theta/2)
distance = √[0-sintheta/2]² + [cos theta/2- 0]²
= √(sin ²theta/4 + cos² theta/4
=√(sin² theta + cos² theta) 4
= √1/4 {since sin² theta + cos²theta = 1}
=1/2
sreedhar2:
good
Thank you
Answered by
16
answer is 1/2
step by step explanation of the sum
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